What is the sum of all the triangular numbers that are between 1 and 100 (inclusive)?
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Now, we know that a triangular number can be represented by the formula :-
2
(
n
)
(
n
+
1
)
When
n
=
1
triangular number =
1
When
n
=
2
triangular number =
3
When
n
=
3
triangular number =
6
When
n
=
4
triangular number =
1
0
When
n
=
5
triangular number =
1
5
When
n
=
6
triangular number =
2
1
When
n
=
7
triangular number =
2
8
When
n
=
8
triangular number =
3
6
When
n
=
9
triangular number =
4
5
When
n
=
1
0
triangular number =
5
5
When
n
=
1
1
triangular number =
6
6
When
n
=
1
2
triangular number =
7
8
When
n
=
1
3
triangular number =
9
1
When
n
=
1
4
triangular number =
1
0
5
So, we see that the largest triangular number smaller than 1 0 0 is 9 1 for which ( n = 1 3 )
So, all we have to do is evaluate n = 1 ∑ 1 3 = 4 5 5 .
Simple standard approach.
1 + 3 + 6 + 10 + 15 + 21 + 28 + 36 + 45 + 55 + 66 + 78 + 91
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triangular numbers are those numbers of objects that could create an equilateral triangle. like 3, 6, 10, etc.. Between 1 and 100, these are the triangular numbers: 1, 3, 6, 10, 15, 21, 28, 36, 45, 55, 66, 78 and 91 which sum up to 455.