Sum of Triangular Numbers

What is the sum of all the triangular numbers that are between 1 and 100 (inclusive)?


The answer is 455.

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3 solutions

Val Irvin Mabayo
Jun 16, 2014

triangular numbers are those numbers of objects that could create an equilateral triangle. like 3, 6, 10, etc.. Between 1 and 100, these are the triangular numbers: 1, 3, 6, 10, 15, 21, 28, 36, 45, 55, 66, 78 and 91 which sum up to 455.

Ashish Menon
Mar 26, 2016

Now, we know that a triangular number can be represented by the formula :- ( n ) ( n + 1 ) 2 \dfrac {(n)(n+1)}{2}
When n = 1 n =1 triangular number = 1 1
When n = 2 n =2 triangular number = 3 3
When n = 3 n =3 triangular number = 6 6
When n = 4 n =4 triangular number = 10 10
When n = 5 n =5 triangular number = 15 15
When n = 6 n =6 triangular number = 21 21
When n = 7 n =7 triangular number = 28 28
When n = 8 n =8 triangular number = 36 36
When n = 9 n =9 triangular number = 45 45
When n = 10 n =10 triangular number = 55 55
When n = 11 n =11 triangular number = 66 66
When n = 12 n =12 triangular number = 78 78
When n = 13 n =13 triangular number = 91 91
When n = 14 n =14 triangular number = 105 105



So, we see that the largest triangular number smaller than 100 100 is 91 91 for which ( n = 13 ) (n = 13)

So, all we have to do is evaluate n = 1 13 \displaystyle \sum_{n=1}^{13} = 455 \boxed {455} .

Moderator note:

Simple standard approach.

Maxwell Johnson
Jun 16, 2014

1 + 3 + 6 + 10 + 15 + 21 + 28 + 36 + 45 + 55 + 66 + 78 + 91

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