Sum Of Two Squares Is Zero

The value of the discriminant here is in negative.So it has 2non real roots .

$(x+1)^2=-9$ or $x=\boxed{{\pm3i-1}}$ . Thus the equation has two non-real roots.

For the quadratic equation $Ax^2 + Bx + C = 0$ ,

if $B^2 = 4AC$ , the roots are equal

if $B^2 > 4AC$ , the roots are real and distinct

if $B^2 < 4AC$ , the roots are imaginary or non-real.

$(x + 1)^2 + 3^2 = 0$ $\implies$ $x^2 + 2x + 10 = 0$ $\mapsto$ $B^2 < 4AC$ $\therefore$ The roots are non-real.