Sum Power

Algebra Level 3

for 2 number (a,b) exist such the a b = a + b a^b=a+b and b a = b a b^a=b-a what is ( a a a b b ) a / a 2 a (a^a*a^b*b)^a/a^2a

(a+b)^2 b^2 2ab There's no way to no

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1 solution

שחר א.
Aug 18, 2018

consider a b a a a^b*a^a is a^ a + b a+b which is a^a^b , factoring, you get a^a^(b-1) a. move out the first part out and the parentasis and get (a^a^(b-1))^a which is a ( a b ) a^(a^b) . Once again, replace a^b by a+b and get a a a b a^a*a^b (ab)^a. a a a b a a b a a^a*a^b*a^a*b^a = ( a a ) 2 ( b + a ) ( b a ) (a^a)^2*(b+a)*(b-a) = ( a 2 a ) ( a 2 b 2 ) (a^2a)*(a^2-b^2)

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