Here are the rules of sum Sudoku :
What can we conclude about the circle sums in the puzzle?
Example:
The setup in the top-left box is valid since
. However, the four cell values at the center are invalid since
.
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Let's look at the cells adjacent to the center circle.
Since a = b , it is impossible for the center sum to exist. Suppose that it is possible to label common digit in adjacent cells at the center. Along one of the diagonals, label a and b , where a + b = 5 (since the circle sum within the box is unique). Value-searching, we have the setup as shown above. However, since the pairs of a 's and b 's are adjacent to the center circle, this shows that 2 a = 2 b , which is impossible since this violates the first rule.
Therefore, no opposite cells can have common values. Because 5 is the only number that can be expressed as two different integer sums, all circle sums must be the same .
It is easy to notice that since the puzzle is symmetric about the center circle, we can either reflect or rotate it to determine other solutions!