If and are positive integers satisfy the equation above , where is square-free , find .
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S ⟹ S = k = 1 ∑ ∞ 2 0 1 7 k k = k = 0 ∑ ∞ 2 0 1 7 k k = k = 0 ∑ ∞ 2 0 1 7 k + 1 k + 1 = 2 0 1 7 1 ( k = 0 ∑ ∞ 2 0 1 7 k k + k = 0 ∑ ∞ 2 0 1 7 k 1 ) = 2 0 1 7 1 ( S + 2 0 1 6 2 0 1 7 ) = 2 0 1 6 2 2 0 1 7
⟹ a + b = 2 0 1 7 + 2 0 1 6 = 4 0 3 3