Sum to n terms

Number Theory Level pending

1 + 8 + 27 + 64 + 125 + . . . 1+8+27+64+125+ . . . up to 1 0 t h 10^{th} term is?

1024 3025 1025 3024

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1 solution

Zeeshan Ali
Jan 26, 2015

sum to n terms of the given series 1+8+27+64+125+........ is {n(n+1)/2}^2 therefore {10(10+1)/2}^2={55}^2=3025

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