Summated Integral!

Calculus Level 3

[ ∑ n = 1 10 ∫ − 2 n − 1 − 2 n sin 27 x dx ] + [ ∑ n = 1 10 ∫ 2 n 2 n + 1 sin 27 x dx ] = ? \left[\displaystyle\sum_{n=1}^{10}\displaystyle\int_{-2n-1}^{-2n}\text{sin}^{27} \text{x dx}\right]+ \left[\displaystyle\sum_{n=1}^{10} \displaystyle\int_{2n}^{2n+1}\text{sin}^{27} \text{x dx}\right] = \ ?

Answer upto two decimals.


The answer is 0.00.

View wiki
Parth Lohomi by Parth Lohomi , 20, India

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Incredible Mind
Mar 13, 2015

it is odd function meaning for each integral of first sum,there is its negative on 2ns sum

OR

maybe just sub. x= -u in first sum ,then see the what happens

2 Helpful 0 Interesting 0 Brilliant 0 Confused

nice thinking!

Parth Lohomi - 6 years, 3 months ago
Harsh Soni
Mar 14, 2015

L 00 00 k!ng c u m b e r s o m e cumbersome T R I C K Y TRICKY

0 Helpful 0 Interesting 0 Brilliant 0 Confused

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...