Credible sums

Algebra Level 4

If ( 1.5 ) 30 = k (1.5)^{30}=k , then state n = 2 29 ( 1.5 ) n \displaystyle\sum_{n=2}^{29}(1.5)^{n} in terms of k k .

none of these 2 k 3 2k-3 2 k + 1 2k+1 2 k 9 2 2k-\frac{9}{2} 2 k + 7 2k+7 \infty

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1 solution

Ravi Dwivedi
Jul 4, 2015

The required expression is a G.P. with first term= (1.5)^2 and common ratio=1.5

Let the expression to be calculated be E.

E=

=

=

=

=

Moderator note:

Simple standard approach

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