Summer of '69.

Level pending

Mr. John Doe was born on January 1st, 19xx.

It is known that January 1st, 1900 was a Monday and that Mr. John Doe died on in the summer of 1969.

If the probability that Mr. Doe was not born on a Thursday or a Saturday is given as x % x\% , what is x x ?


The answer is 74.2857.

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1 solution

It is clear that Mr. Doe's birthday was January 1st and he was born in an year between 1900-1969. (i.e.,70 dates)

The number of days in a normal year is 365 = 1 m o d 7 365 = 1 \mod 7 and 366 = 2 m o d 7 366 = 2 \mod 7 .

The day on which 1st January falls on a particular year can be deduced as

J a n 1 ( x ) = { ( J a n 1 ( x 1 ) + 1 ) m o d 7 , If x-1 is not a leap year ( J a n 1 ( x 1 ) + 2 ) m o d 7 , If x-1 is a leap year Jan1(x) = \left\{\begin{array}{ll} (Jan1(x-1)+1) \mod 7, & \mbox{If x-1 is not a leap year}\\ (Jan1(x-1)+2) \mod 7, & \mbox{If x-1 is a leap year} \end{array}\right.

Using this formula and remembering that 1900 was not a leap year, it can be seen that January 1st was a Thursday in nine years (1909, 1915, 1920, 1926, 1937, 1943, 1948, 1954, 1965) and a Saturday for nine years (1905, 1911, 1916, 1922, 1933, 1939, 1944, 1950, 1961, 1967).

Thus, the probability of the year not starting on a Thursday or a Saturday is 70 18 70 = 0.74286 = 74.286 % \frac{70-18}{70}=0.74286=\boxed{74.286\%}

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