Find the value of -
(
4
)
.
(
1
+
4
5
)
.
(
1
+
9
7
)
.
.
.
.
.
.
.
.
.
.
.
.
(
1
+
4
0
5
2
1
6
9
4
0
2
7
)
.
(
1
+
4
0
5
6
1
9
6
4
0
2
9
)
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Excellent and elegant :)
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What? Level 3 ???? Sorry Krish but it was not of that standard!!! Looking forward to your 1000th follower! And I am looking forward to my 100th follower!! :( :P
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@Kartik Sharma -I am a huge fan of your brilliance..this problem's now back to lvl 2..happy??/
Try to observe the pattern---
(4).(9/4).(16/9).......(4056196/4052169).(4060225/4056196)
Here,you can observe that---numerator of the terms are same as the denominator of the next term to them,except the last term.So,
(1).(1/1).(1/1)....(1/1)(4060225/1)=4060225
Just observe the pattern. Everything else cancels out except the last term
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The product becomes n = 1 ∏ 2 0 1 4 ( 1 + n 2 2 n + 1 ) = n = 1 ∏ 2 0 1 4 n 2 ( n + 1 ) 2 = 2 0 1 5 2 = 4 0 6 0 2 2 5 ~~~