Super Slick Simplification

Algebra Level 1

( 0 3 350 ) ( 1 3 349 ) ( 2 3 348 ) ( 3 3 347 ) ( 34 9 3 1 ) ( 35 0 3 1 ) \large (0^3-350)(1^3-349)(2^3-348)(3^3-347) \ldots (349^3-1)(350^3-1)

Express as accurately as possible, the value of the product above.


The answer is 0.

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6 solutions

Aayush Gupta
Jul 1, 2014

Notice that the seventh parentheses is ( 7 3 343 ) (7^3-343) , which is 0 0 . This makes the whole product 0 \boxed{0} .

GOSH!! Awesome...

Satvik Golechha - 6 years, 11 months ago

Wow! What a troll!

Alex Segesta - 6 years, 10 months ago

superb!!!!!!

Rishi Hazra - 6 years, 10 months ago

Tremendous Problem!!

Anik Mandal - 6 years, 10 months ago

made me crazy!!

Palash Som - 6 years, 10 months ago

Yeah exactly bro... Seventh bracket make it all.. Cooool Problem @Aayush Gupta ... Awesome...... :-D

Akshay Sant - 6 years, 10 months ago

As accurately as possible... that got me.

Tan Wee Kean - 6 years, 10 months ago

I did exactly same way..

Bhupendra Jangir - 6 years, 3 months ago
Curtis Clement
Mar 3, 2015

The expression can be rewritten as : r = 1 350 ( r 3 + r 350 ) \displaystyle\prod_{r=1}^{350} (r^3 +r -350) r 3 + r 350 = 0 r = 7 r = 1 350 ( r 3 + r 350 ) = 0 \rightarrow\ r^3+r-350 = 0 \Rightarrow\ r=7 \therefore\displaystyle\prod_{r=1}^{350} (r^3 +r -350) = \boxed{0}

Islam Shahin
Jun 27, 2015

Write a solution. Prod. (n^3+n-350) @ n = 7 ---> the value will be 0

Ayush Sharma
Apr 28, 2015

If you just follow the pattern there, you will notice that the the seventh term in this whole is ( 7 3 343 ) (7^3-343) which is the same as 0.So, the expression simplifies to 0 \boxed{0} .

Mahmood Helal
Mar 7, 2015

since ( 7 3 343 = 0 ) (7^3-343=0) , the whole expression gets 0

Fox To-ong
Jan 14, 2015

any number multiplied by zero is zero.

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