( 0 3 − 3 5 0 ) ( 1 3 − 3 4 9 ) ( 2 3 − 3 4 8 ) ( 3 3 − 3 4 7 ) … ( 3 4 9 3 − 1 ) ( 3 5 0 3 − 1 )
Express as accurately as possible, the value of the product above.
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GOSH!! Awesome...
Wow! What a troll!
superb!!!!!!
Tremendous Problem!!
made me crazy!!
Yeah exactly bro... Seventh bracket make it all.. Cooool Problem @Aayush Gupta ... Awesome...... :-D
As accurately as possible... that got me.
I did exactly same way..
The expression can be rewritten as : r = 1 ∏ 3 5 0 ( r 3 + r − 3 5 0 ) → r 3 + r − 3 5 0 = 0 ⇒ r = 7 ∴ r = 1 ∏ 3 5 0 ( r 3 + r − 3 5 0 ) = 0
Write a solution. Prod. (n^3+n-350) @ n = 7 ---> the value will be 0
If you just follow the pattern there, you will notice that the the seventh term in this whole is ( 7 3 − 3 4 3 ) which is the same as 0.So, the expression simplifies to 0 .
since ( 7 3 − 3 4 3 = 0 ) , the whole expression gets 0
any number multiplied by zero is zero.
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Notice that the seventh parentheses is ( 7 3 − 3 4 3 ) , which is 0 . This makes the whole product 0 .