Supporting a Sphere

A metal bowl is in the shape of a partial unit sphere centered on the origin. The bowl's mass is 1 kg 1 \, \text{kg} , and gravity is 10 m/s 2 10 \, \text{m/s}^2 in the z -z direction.

x = cos θ sin ϕ y = sin θ sin ϕ z = cos ϕ 0 θ 2 π π 6 ϕ π \large{x = \cos \theta \, \sin \phi \\ y = \sin \theta \, \sin \phi \\ z = \cos \phi \\ 0 \leq \theta \leq 2 \pi \\ \frac{\pi}{6} \leq \phi \leq \pi}

A force is applied normally at all points on the outside surface, such that each unit of surface area experiences an infinitesimal force of the same magnitude:

d F d S = α \large\frac{d \, |F|}{d S} = \alpha{}

In the above equation, the units on α \alpha are N/m 2 \text{N/m}^2 (it is therefore a pressure value). If the applied force keeps the bowl in stasis, what is the value of α \alpha ?


The answer is 12.732.

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