Surfaced Area of a Composite Figure

Geometry Level 2

The above figure is a solid with uniform thickness of 2 inches and is symmetrical in shape. Find the surfaced area of the solid in square inches.

Note: All dimensions in the figure are in inches.

16 π + 64 16\pi+64 24 π + 50 24\pi+50 24 π + 80 24\pi+80 24 π + 64 24\pi+64

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1 solution

A = A= 2 ( π r + 4 ) + 0.5 ( π r 2 ) ( 2 ) + 8 ( 2 ) ( 2 ) + 3 ( 2 ) ( 6 ) + 4 2(πr+4) + 0.5(πr^2)(2)+8(2)(2) + 3(2)(6) + 4 = 8 π + 8 + 16 π + 32 + 40 = 24 π + 80 =8π+8+16π+32+40=24 π+80

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