Sweets in a Bag

This can be solved by algebra, but there is also a nice intuitive way, which uses the fact that before and after, the number of non-green sweets stays the same!

Before, there were $24$ green sweets, and therefore $96$ non-green sweets.

Afterwards, the $96$ non-green sweets account for three quarters of the sweets in the bag. As the number of green sweets is now one quarter of the bag, there must be $\frac{96}{3}=32$ green sweets.

Therefore I added $32-24=\boxed{8}$ sweets.

$number~of~green~sweets=\dfrac{1}{5}(120)=24$

Let $G$ be the number of green sweets to be added, then,

$\dfrac{1}{4}(120+G)=96+4G$

Multiplying both sides of the equation by $4$ , we get

$120+G=96+4G$

$120-96=3G$

$\boxed{G=8}$ $\color{#D61F06}\boxed{answer}$

green sweets=120*1/5=24
Now required to find out ' how many sweets to be added to make 1/4 of the sweets in the beg...........
(24+x)4=120+x
X=8 (Ans.)