Switch Open,Switch Closed

Electricity and Magnetism Level 1

A battery has an EMF (Electromotive Force ) of 6 V \displaystyle 6\text{ V} and an internal resistance of 0.4 Ω \displaystyle 0.4 \ Ω . It is connected to a 2.6 Ω \displaystyle 2.6\ Ω resistor through a SPST (single pole, single throw) switch.

Find the potential difference between the terminals of the battery when the switch is open and when the switch is closed, in volts.

( 0 , 6.0 ) (0 ,6.0 ) ( 1.6 , 6.0 ) (1.6 ,6. 0) ( 0.8 , 5.2 ) (0.8,5.2 ) ( 6.0 , 5.2 ) (6.0 ,5.2 )

Fahim Shahriar Shakkhor by Fahim Shahriar Shakkhor , 24, Bangladesh

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1 solution

Azadali Jivani
Jan 24, 2017

Tot.Res.=0.4+2.6 = 3 ohms
I=V/R=6/3 = 2 amps
Voltage across 2.6 ohms = IR = 2*2.6 = 5.2 Volts (closed ckt. voltage)
Open ckt. Voltage = 6 Volts

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