Sylogistically logical

Logic Level 3

Let A = { 1 , 2 , 3 , 4 } \text{A} = \{1,2,3,4\} and R = { ( 1 , 1 ) , ( 2 , 2 ) , ( 3 , 3 ) , ( 4 , 4 ) , ( 1 , 2 ) , ( 4 , 3 ) , ( 3 , 2 ) , ( 2 , 1 ) , ( 3 , 4 ) } \text{R} = \{(1,1),(2,2),(3,3),(4,4),(1,2),(4,3),(3,2),(2,1),(3,4)\} be a relation on A \text{A} . Then is R \text{R} transitive?

No Insufficient information Yes

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1 solution

Ashish Menon
Jul 5, 2016

In the set R \text{R} according to ( 3 , 2 ) (3,2) 3 3 is related to 2 2 , according to ( 4 , 3 ) (4,3) , 4 4 is related to 3 3 , but it should contain ( 4 , 2 ) (4,2) meaning that 4 4 is related to 2 2 which is absent in the set. Thus R \text{R} is not \color{#3D99F6}{\boxed{\text{not}}} transitive.

Your example shows that R R is not symmetric, but does not address the matter of transitivity. To this end, we note that with ( 4 , 3 ) (4,3) and ( 3 , 2 ) (3,2) being elements of R R we would require that ( 4 , 2 ) (4,2) also be an element of R R for it to be transitive, which is not the case, thus proving that R R is not transitive.

Brian Charlesworth - 4 years, 11 months ago

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Thanks! I changed it! :)

Ashish Menon - 4 years, 11 months ago

I answered insufficient information. I feel it is the same as saying the solution does not indicate that our relation is not transitive. There is a misleading answer in your answer.

Hana Wehbi - 4 years, 11 months ago

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