Tickets To Annual Talent Show

students quantity remains same.... 3 seniors increases..and the increase value of dollars divide by 3...

let, senior citizen = x and students= y so that , 4x + 5y = $102..........(1) 7x + 5y = $126..........(2) to solve equations we get, x=8 ( senior citizen ).....ans

Let us say that Senior Citizen=a and student=b

4a=5b=$102 7a=5b=$126 Then eliminate the two solutions. You will get: 3a=$24 a=$8 Easy!!!

Let x be the price for senior citizens

and y be the price for students,By conditions we get

4x+5y=102.............[1]

7x+5y=126.............[2]

By subtracting equation [2] from [1],we get

-3x=-24

x= -24/-3

x=8$

Let cost of senior citizen's ticket be \­(x\­) and student's ticket be \­(y\­).

Given, \­(4x\quad +\quad 5y\quad =\quad 102\­) and

\­(7x\quad +\quad 5y\quad =\quad 126\­)

It can clearly be seen that second equation is \­(3x\­) more than first one.

Difference in the answer = \­(126\quad -\quad 102\quad =\quad 24\­)

Therefore, \­(3x\quad =\quad 24\­)

\­(x\quad =\quad \frac { 24 }{ 3 } \­)

\­(x\quad =\quad 8\­)

So, the cost of Senior Citizen's ticket is 8.

4x+5y=102...........(1) 7x+5y=126...........(2) by sloving this 2 eqns we find that x=8 ;)

Let x be the price for senior citizens

and y be the price for students,By conditions we get

4x+5y=102.............[1]

7x+5y=126.............[2]

By subtracting equation [2] from [1],we get

-3x=-24

x= -24/-3

x=8$

no. of students remain same subtracting second one from first one we get 3 seniors need Rs.24 so , one senior cost Rs. 8

4x+5y=102...............................where x is the price of senior citizen ticket & y is student ticket. 7x+5y=126 By solving the eqn we get the answer like x=8 & y=14. So the price of each of the senior ticket is $8

let the price of each student ticket be x and that of senior ticket be y. according to the question, 4x+5y=102 and 7x+5y=126 in both the equations we see that 5y is common, so, we can take that 102-4x=126-7x on solving we get x(price of each senior ticket) =8

4 senior citizen+5 student =102$ 7 senior citizen+5 student=126$ from above two we can say that number of citizen increased=3 and money increased is 126-102=24 therefore 1 senior citizen =24/3=8

4X+5Y=102 and 7X+5Y=126 where X=S.c and Y=st Calculate two equation we get X=8

let , a be the cost of ticket foe senior citizen and b be the cost of ticket foe the student

in first day,

he sold 4 ticket for senior citizen and 5 for student at the cost of $102 therefore,

4a + 5b =102

4a + 5b -102 = 0------------------------------------- equation 1

in second day,

he sold 7 ticket for senior citizen and 5 for student at the cost of $126

7a + 5b =126

7a + 5b -126 = 0------------------------------------- equation 11

solving 1 and ii

we get, 3a - 24=0

3a = 24

a=24/3

a=8

cost of ticket for senior citizen =$ 8

7-4= 3

126-102= 24

24÷3= 8

let, senior citizen = x and students= y so that ,

4x + 5y = 102 ............(1)

7x + 5y = 126 ............(2)

-3x = -24

x = -24/-3

x = 8

Assume a = senior and b = student

At first day:

$4a + 5b = 102$

At second day:

$7a + 5b = 126$

we can see that in second day, only 3 more senior ticket has sold, so we will have $3a = 126 - 102 = 24$ $a = 8$

126-102= 24 because they have a same number of students you should to subtract it. and the difference, divide in to 3 7-4=3 24/3=8

1st Day

4x+5y= 102

2nd Day

7x+5y=126

7x-4x=3x and 126-102=24 So x=8

4 SC + 5 St = 102 and 7SC + 5 St = 126 From the above, 1 SC = $ 8

1st Day

4x+5y= 102

2nd Day

7x+5y=126

The student ticket number is same for both day, the only difference is in the senior ticket so $7x-4x = 3x$ and $126-102 = 24$ So x=8.

Senior Citizen's ticket = x

Student's ticket = y

So,

4x + 5y = 102 therefore 5y = 102 - 4x -- (1)

7x + 5y = 126 therefore 5y = 126 - 7x -- (2)

(1) = (2)

126 - 7x = 105 - 4x

126 - 105 = -4x + 7x

24 = 3x

x = 8

Simple!

7x + 5y = 126 .......eq1

-(4x + 5y) = -(102) ........eq2

3x =24; x =24/3; Therefore x= 8

(4x+5y)-(7x+5y)=102-126 = -3x=-24 = x=8

Suppose "X" be ticket price for the senior citizen

4x+5y=102 - Eq. (1)

7x+5y=126 - Eq. (2)

Subtracting Eq. (2) by (1)

7x+5y=126

4x+5y=102

- - = -

3X+0=24

3X=24

X=24/3

[ X=8] Ans.

You can put this X into any equation to get value of "Y" Thanks

(7x+5y)-(4x+5y)=(126-102) or,3x=24

4x+5y=102 and 7x+5y=126 (x=8)

solve the equations : 4x+5y=102 and
7x+5y=126

 where  x=charge of a senior citizen
              y=charge of a student

Take senior citizen ticket 'a' and student 'b'. the the 1st codition becomes 4a+5b= 102. and second codition becomes 7a+5b=126. equating the thes two equetion we get 3a=24. and 5b get cancel.therfor the value of a (senior citizen ticket)=8

Let the value of senior citizen ticket be 'x', and 'y' the value of student ticket. The two equations become: 4x+5y=102---->eq(i) 7x+5y=126---->eq(ii) By eliminating y from the above equations using substitution method we can find the value of x. 4x+5y=102 => y=102-4x/5----->eq(iii) By substituting the value of y in eq(ii) the equation becomes: 7x+5(102-4x/5)=126 => x=8

solving it in systems ....let a= senior tickets ... let b= children tickets i used subtraction to eliminate the children tickets

7a+5b=126 ---> 2nd given

- 4a+5b=102 ---->1st given

3a = 24

3a/3 = 24/3 a= 8

4x+5y=102, 7x+5y=126, here, 'x' is senior ticket's prize and 'y' is student's ticket prize. So on solving these two equations for x, we get x=$8.

in first and 2nd day student quantity remains same only senors quntity incresse 3 and cost incresses 24 so 24/3=8

Let the price ticket for an seniors be x & for students be y. Therefore 4x + 5y = 102.....................eq 1 7x + 5y = 126......................eq 2 Subtracting eq 1 from eq 2 we get 3x=24 x=8 Ans is 8.

There is no difference between the student ticket sale on both days. So, we take the difference of the senior citizen tickets and the difference of the total amount of money. Then, just divide the difference of the total amount of money and the difference of the senior citizen tickets.

Hello, let the ticket prices of senior citizen = x , student = y,

4x + 5y = 102

7x + 5y = 126 , by eliminating of y,

-3x = -24

x = 8 , y = 14

therefore , x = $8 each...

In each case,the number of students are same.But the number of senior citizen increases and the amount of dollar also increases. 24 dollars are increased for 3 senior citizen. so 8 dollars for each senior citizen.