T in a Triangle

Geometry Level 2

Triangle A B C ABC is equilateral. Line segments E D \overline{ED} and F G \overline{FG} are perpendicular and share the same length. Line segment E D \overline{ED} is parallel to A C \overline{AC} .

Not to scale. Not to scale.

What is x s \frac{x}{s} if x x is the length of either E D \overline{ED} or F G \overline{FG} and s s is the side length of A B C \triangle ABC ?

NOTE: The answer must be in the nearest thousandths.


The answer is 0.4641.

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2 solutions

sin 60 ° = x s x \sin 60\degree=\dfrac {x}{s-x}

3 2 = x s x x s = 3 2 + 3 0.4641 \implies \dfrac {\sqrt 3}{2}=\dfrac {x}{s-x}\implies \dfrac {x}{s}=\dfrac {\sqrt 3}{2+\sqrt 3}\approx \boxed {0.4641} .

Kaizen Cyrus
Jul 14, 2020

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