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1 solution
T z = 2 z + 1 2 z − 1 = 2 1 ⟹ 2 z − 1 = 4 2 z + 2 1 ⟹ 0 = 4 0 z + 2 2 ⟹ z = − 4 0 2 2 = − 2 0 1 1 .