Tailoring Profits

Algebra Level pending

In the month of January, a tailoring company has 1000 yards of fabric and 1800 man-hours to produce shirts and suits. It takes 1 yard of fabric with 2 hours to time to make a shirt, and 2 yards of fabric with 3 hours of time to make a suit.

Given the costs of inputs, they can make $12 selling a shirt and $20 selling a suit. What is the maximum profit of the tailoring company in January?

$11200 $10000 $10800 $12000

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1 solution

Tom Engelsman
Dec 1, 2016

Let x x be the total number of shirts & y y be the number of suits produced. We now formulate the following linear program model:

M A X 12 x + 20 y MAX 12x + 20y

SUBJECT TO:

x + 2 y 1000 x + 2y \le 1000

2 x + 3 y 1800 2x + 3y \le 1800

x , y 0 x, y \ge 0

where the first and second constraints represent the necessary fabric and manhours respectively. If we plot the above constraints in the x y xy- plane, we obtain the feasible region containing the vertices ( x , y ) = ( 0 , 0 ) ; ( 0 , 500 ) ; ( 600 , 200 ) ; ( 900 , 0 ) (x,y) = (0, 0); (0, 500); (600, 200); (900, 0) . The profit is maximized at ( x , y ) = ( 600 , 200 ) (x,y) = (600, 200) , or ( $ 12 ) ( 600 ) + ( $ 20 ) ( 200 ) = $ 11 , 200 (\$12)(600) + (\$20)(200) = \$11,200 after checking each critical vertex.

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