Take care, it's jerking!

The jerk of the body is given by:

$\begin{aligned} j(t) & = \frac {d^3 x(t)}{dt^3} \\ & = \frac {d^2}{dt^2} \left( \frac d{dt} \left(8t^4 + 5t^3 + 2t^2 + 4t + 1\right) \right) \\ & = \frac d{dt} \left( \frac d{dt} \left(32t^3 + 15t^2 + 4t + 4 \right) \right) \\ & = \frac d{dt} \left(96t^2 + 30t + 4 \right) \\ & = 192t + 30 \\ \implies j(1) & = 192+30 = \boxed{222} \text{ ms}^{-3} \end{aligned}$

$\begin{aligned} x & = 8t^4 + 5t^3 + 2t^2 + 4t + 1\\ \\ \dfrac{d}{dt} x & = \dfrac{d}{dt} \left(8t^4 + 5t^3 + 2t^2 + 4t + 1\right)\\ \\ v & = 32t^3 + 15t^2 + 4t + 4\\ \\ \dfrac{d}{dt} v & = \dfrac{d}{dt} \left(32t^3 + 15t^2 + 4t + 4\right)\\ \\ a & = 96t^2 + 30t + 4\\ \\ \dfrac{d}{dt} a & = \dfrac{d}{dt} \left(96t^2 + 30t + 4\right)\\ \\ j & = 192t + 30\\ \\ \therefore \text{at t=1}\\ j & = 192(1) + 30\\ \\ & = \color{#3D99F6}{\boxed{222}} \end{aligned}$