Take off
An aeroplane requires for takeoff a speed of 80km/hr. the run on the ground being hundred meter . the mass of the plane is 10,000kg and the coefficient of friction between plane and ground is 0.2.assume that the plane accelerate uniformly during the takeoff.what is the minimum force required by its engine for takeoff ? (In NEWTON(N)).
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
1 solution
initial velocity,u =0
final speed = 80 km/h = 80 5/18 m/s = 200/9 m/s
displacement, s = 100 m
let a be the acceleration produced, then using
v^2-u^2 = 2 as, we have
(200/9)^2 - (0)^2 = 2 a 100
a = 200 200/9 9 100 = 200/81 m/s ^ -2
force required = ma = (10,000) 200/81 N
force required to overcome friction,
f2 = mewN=mewmg
=0.2 10,000*9.8 N
total force = f1+f2 = 44291.3