Take the game till the root!

Algebra Level 3

If α \alpha and β \beta are the distinct roots of the equation

x 2 + x α + β = 0 x^2 + x\sqrt{\alpha} + \beta = 0

what is the value of α + β \alpha+\beta ?


The answer is -1.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Tom Engelsman
Aug 25, 2017

If we have x 2 + α x + β = 0 ( x α ) ( x β ) = 0 x^2 + \sqrt{\alpha}x + \beta = 0 \Rightarrow (x-\alpha)(x-\beta) = 0 , then by Vieta's Formulae we have:

α + β = α ; \alpha + \beta = -\sqrt{\alpha};

α β = β \alpha \beta = \beta

which solves as α = 1 , β = 2 \alpha = 1, \beta = -2 , and α + β = 1 . \alpha + \beta = \boxed{-1}.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...