Taking out factors

Find the number of unordered pairs ( x, y ) for which the following equation is satisfied x 4 y 4 = 2007196 x^{4} - y^{4} = 2007196 where x,y are integers.


The answer is 0.

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2 solutions

Yuxuan Quek
Nov 19, 2014

One can see that the number is divisible by 4, and not 8. Therefore of the three terms in (x^2+y^2)(x+y)(x–y), at least 1 term and at most 2 terms can be even.

Consider x and y both even; in that case, all 3 terms would be even. Consider that only one of x or y are even; in that case, none of the terms are even. Consider that both x and y are odd; in that case all 3 terms are even. Therefore no values of x and y can satisfy that equation. There's no need to factorize out the number completely.

Sunil Pradhan
Oct 8, 2014

x^4 – y^4 = (x^2+y^2)(x+y)(x–y) , 2007196 = 12239 × 41 × 4

12239, 41 being prime and odd considering (x+y) = 41 and (x – y) = 4

No. integer value of x and y

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