8 men complete one third of the work in 5 days. How many more men should be employed to finish the rest of the work in 4 days?
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In these kind of problems, always note that.....
¤ More men less days & conversely more days less men.
¤ More men more work & conversely more work more men
¤ More days more work & conversly more work more days.
So if M1 persons can do W1 work in D1 days and M2 persons can do W2 work in D2 days then we have a general formula as shown below...
(M1)(D1)(W2)= (M2)(D2)(W1)
==> (8)(5)(2/3) = (M2)(4)(1/3)
==> M2=20
So (20-8) = 12 more men required to finish rest of the job.