Tall men next door

Algebra Level 3

next to my house live four brothers of different heights. their average height is 74 inches, and the difference in height between the first three men is two inches. The difference between the third and fourth man is six inches . Find the height of each person. Write the height from first person to fourth person in order and put a zero after each height. Pls don't mention inches. Suppose heights are A,B,C,D then give answer as A0B0C0D.


The answer is 70072074080.

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1 solution

Ishaan Panda
Jun 12, 2015

As average height is 74 inches, therefore sum of heights of four men is 296 inches. Next we construct equation for the four people. Let the heights of the people be a, b, c, d in increasing order. then a+2=b b+2=c c+6=d Now equating all the heights in terms of d, we get c=d-6 b+2=d-6; b=d-8 a+2=d-8; a=d-10 a+b+c+d=296; (d-10)+(d-8)+(d-6)+d=296 Thus we get d=80, c=74, b=72, a=70. 70,72,74,80.

great solution I like it

Rwit Panda - 5 years, 11 months ago

it may be 70 68 66 60 also i think so

nayakam Vardhan vardhan - 2 years, 8 months ago

I can come up with a different answer by assuming person a is the tallest, not the shortest. Heights are then 68, 74, 76, 78 (after sorting into ascending order).

David Blick - 5 years, 11 months ago

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It is given that the difference in heights between the first three men is 2 inches. That's where your answer does not match.

Ishaan Panda - 5 years, 11 months ago

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A is 78, B is 76, C is 74. The difference between each is 2 inches. D is 68. The difference between C and D is 6 inches.

David Blick - 5 years, 11 months ago

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