Tallest and shortest among group of 10000 men

10000 men are arranged in an array of 100 rows and 100 columns according to their heights.

Tallest among each row of all are asked to come out. And the shortest among them is A.

Similarly after resuming them to their original positions, the shortest among each column are asked to come out. And the tallest among them is B.

Now who is taller A or B?

A < B A < B Lack of information A = B A=B This question is flawed A > B A > B

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2 solutions

Hypothetically thinking of a 100 x 100 matrix filled with numbers starting from 1 and going upto 10000. The smallest of the largest number going row wise would be 100. And the largest of the smaller numbers going column wise would be 100. Thus A = B

The shortest man of the tallest is the same tallest man of the shortest. Imagine that you sort them in ascending order and pick one. He will be the tallest of the short men and the shortest of the tall men. It does not matter how many people is there.

Maybe I'm confused. If we arrange these men in such a way that each row has 1 person of height 100, and everyone else is height 1, then these 100 will be the tallest for their row. The shortest for these guys is 100. These guys all happen to be in different collumns. So when we examine, each column has a guy that guy that is height 1.The tallest of these guys is 1.

Frank Rodriguez - 6 years, 2 months ago

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The problem didn't specify "according to height"

Frank Rodriguez - 6 years, 2 months ago

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He is right. B<=A

Hasmik Garyaka - 3 years, 8 months ago

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