Taming the Radix

What is the length of the base-10 numeral 1 9 1234 19^{1234} when expressed in base-3?

Express your answer in base-10.


The answer is 3308.

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1 solution

Arulx Z
Jan 29, 2016

The length of the numeral 1 9 1234 19^{1234} will be 1 more than the highest power of 3 which divides 1 9 1234 19^{1234} . We can formulate this into logarithms and then simplify the answer.

= log 3 19 1234 + 1 = 1234 log 3 19 + 1 =\left\lfloor \log _{ 3 }{ { 19 }^{ 1234 } } \right\rfloor +1\\ =\left\lfloor 1234\log _{ 3 }{ 19 } \right\rfloor +1

Since log 3 19 2.68 \log _{ 3 }{ 19 } \approx 2.68 ,

= 3307 + 1 = 3308 =3307+1\\ =3308

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