Tangen

Geometry Level 2

paragraph 1 What is the value of log tan 1^{o} + log tan 2^{o} + log tan 3^{o} + .... + log tan 89^{o} .

0 -1 1 2

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2 solutions

First, log ( x ) + log ( y ) = log x y \log(x) + \log(y) = \log xy .

Then, tan ( 9 0 x ) = cot x \tan(90^\circ - x) = \cot x

Of course tan ( x ) cot ( x ) = 1 \tan(x)\cot(x)=1

Therefore tan ( 1 ) tan ( 8 9 ) = 1 \tan(1^\circ) \tan(89^\circ)=1 and similarly for 2 and 88, 3 and 87, and any and all other x and y that sum to a right angle.

Finally log 1 = 0 \log 1 = 0

I enjoyed this problem. It's like a trigonometric version of the famous Gauss anecdote .

I wanted to point out, though, that there's a more widely accepted and less ambiguous way to write your degree signs: a superscript \circ , as in 4 5 45^\circ . When your LaTeX compiles properly, the difference between 4 5 o 45^{o} and 4 5 45^\circ is very slight. But if it doesn't compile correctly, nobody's left wondering what "1 to the power of o" means. :)

Michael Hartwell - 4 years, 4 months ago
Nivedita Sharma
Feb 18, 2017

log x + log y =log xy So, log(tan1 tan 2 ........tan89), Now, as = tan(90 -1)=cot 1, And tan1.cot1=1 All will get cancelled except tan45 So, log (tan45) = log1 = 0

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