Two circles are tangent to each other, and their diameters
d
1
and
d
2
satisfy
d
1
×
d
2
=
3
6
.
Segment
A
B
is tangent to both circles. Find the length of
A
B
.
If you think that the length of A B depends on the relative values of d 1 and d 2 , submit your answer as 9999.
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Did the same, good problem +1
The correct answer is 12. As noted in one other comment, (r1+r2)^2=(r2-r1)^2+(CE)^2 The derivative of that formula is equal to (CE)^2=4(r1)(r2) As we we given at the beginning, the product equals 36, so we can simplify the right side to 4(36), which equals 144. Taking the square root leaves you with 12.
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Note the difference between the radius and the diameter.
Best explaination
I would prefer to give that r 1 × r 2 = 9 , so that 3 6 isn't a quick guess. Do you mind if I make the edit?
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I do not mind. You can go ahead.
I meant this to be more of an educational problem than a challenge problem. That is a reason I asked the question in this way. Again, if you want it changed it is OK with me.
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Ah ic. I will leave it in your original form then.
I think it's a great problem too :)
Take 2 circles each of diameter 6
Short cut .....good approach
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( r 1 + r 2 ) 2 = ( r 2 − r 1 ) 2 + C E 2 ⇒ C E 2 = 4 × r 1 × r 2
A B = C E ⇒ A B = d 1 × d 2 = 6 .
In other words, the length of the tangent segment for two externally tangent circles is a geometric mean of their diameters.
Note: This problem was inspired by A text-book of geometry by Wentworth , #235 on page 175.