Let and be two externally tangent circles at with smaller than . Let their common external tangents intersect at . Let a line through intersect circles and at in that order. Given that and , find .
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Connect S with T and call the intersection with ω 1 , T ′ . Positive homothety centered at S maps A → C and T ′ → T . This implies that A T ′ ∣ ∣ T C ⟹ ∠ C T A = 9 0 ∘ .
Thus, △ A T C is a right triangle and Pythagorean theorem, you get that A C = 5 .