Tangent ellipses

Geometry Level 5

There is a circle of a radius 8 3 \sqrt{\frac{8}{3}} . There are 3 ellipses inside the circle which are tangent to the circle at points A , B , C A, B, C and to each other at points D , E , F D, E, F . Their major axes are parallel to lines tangent to the circle at corresponding tangency points. The lengths of major axes of the ellipses are:
2 3 2 2 \sqrt{\frac{3}{2}} , 2 8 7 2 \sqrt{\frac{8}{7}} and 2 2 . X = A B C D E F X = \frac{\triangle ABC}{ \triangle DEF}

Find X × 1000 \lfloor X \times 1000 \rfloor


The answer is 3648.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Maria Kozlowska
Jul 11, 2015

The circle with 3 inscribed tangent ellipses is just a top view of Crelle's tetrahedron incircles. In order for four circles to be tangent to each other the tetrahedron edge lengths have to meet the criteria: a + a = b + b = c + c a + a' = b + b'=c + c' where a a' is an edge opposite to a a (Crelle's tetrahedron).

Edge lengths can be found solving system of 4 equations using formula for the radius of the inscribed circle: r = s r=\frac{\triangle}{s} where s is a semiperimeter of a triangle.
In this case edge lengths are: 5 , 6 , 7 , 3 , 4 , 5 5,6,7,3,4,5 , base side lengths: 5 , 6 , 7 5,6,7 .

Having this information the area of the contact triangle A B C ABC can be found. Geometric construction can be made of a tetrahedron net with 4 circles. Ellipses contact points can be found as points of intersections of lines perpendicular to the sides of the base from circles contact points.

Note: This problem was inspired by Michael Mendrin's Four Tangent Circles

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...