Let e k (for k = 0 , 1 , 2 , 3 , . . . ) be the k th-degree elementary symmetric polynomial in the variables
x i = tan θ i
for i = 0 , 1 , 2 , … i.e.
e 0 = 1
e 1 = i ∑ tan θ i
e 2 = i < j ∑ tan θ i tan θ j
and so forth.
Find the value of
tan ( i ∑ θ i ) .
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I just let i = 3 and found out that the answer is e 0 − e 2 + e 4 − . . . e 1 − e 3 + e 5 − . . .