Consider the tangram set, in which the large square can be split into 7 polygons - 5 triangles, 1 square, and 1 parallelogram.
If we use all 7 pieces to form a convex polygon, what is the greatest number of sides of this polygon?
7
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Tangrams have corners that are 45, 90 ,135 degrees. Any convex polygon of tangrams will have same corner angles of 45 ,90 ,135 because any larger combination at corners create a straight side 180 or a concave >180 angle that is not allowed by definition of convex. Since any polygon can be divided into triangles the sum of interior angles will given by 180*(n-2) so n=7 sides 900 degrees would require angles to include 6(135°)+1(90°) (like an equiangular octagon with 1 edge 2 corners erased and sides extended to point) and with the side lengths number of pieces is not possible to do without holes or leaving out a piece. However there are a few 6 sided solutions (one of which shows how a 7 sided figure could be made with 6 of 7 pieces (remove dark pink))