Tank vs. Artillery

A tank is 222 meters away from an artillery. At this moment, the artillery started bombing at 45 degrees and the velocity was 50 m/s 50\text{ m/s} . Seeing this the tank started to move backward with a velocity of 4 m/s 4\text{ m/s} . What will happen?

Assume g = 10 m/s 2 g=10\text{ m/s}^2 .

bomb will fall 2.5 meters ahead of the tank bomb will fall 28 meters behind the tank bomb will fall 14 meters behind the tank If the velocity of the bomb was 47.12 m/s, it would hit the tank none of these are true The tank will be hit

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1 solution

Burga Burgi
Apr 22, 2016

We know, R= v 2 × s i n ( 2 × θ ) g \frac{v^2 \times sin(2 \times \theta )}{g} . So, on this occasion R=250 meters. Now T= 2 × v × s i n ( θ ) g \frac{2 \times v \times sin(\theta)}{g} = 2 × 50 × s i n ( 45 ) 10 \frac{2 \times 50 \times sin(45)}{10} =7 s (approx.).As the tank will move 4 × 7 4 \times 7 =28 meters in 7 seconds and 28+222=250 meters, IT WILL BE HIT !

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