In the diagram, which tank will become full first?
Details and Assumptions:
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It's a bad drawing, it appears to mix 2D and 3D.Making the answer ambiguous.
I thought 2 and 3 were up in the air, and that 4 and 5 were on the ground. Apparently, all but 1 are sitting on the same plane, which isn't clear from the drawing. If 4 and 5 were the only tanks on the ground, they would be the lowest, and gravity would fill them first, and since 4 is shorter than 5, 4 would fill, and start overflowing before 5 ever got filled, I think.
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Actually, even if that were true, 3 would fill first because it still has a lower top than them, which matters.
This is not necessarily true because, as seen in tank 1, it fills a little but then never gets higher than a certain point.
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Wrong its the tank with the lowest brim (or lowest height) that will overflow first.
This is interesting. Why is it the case that water always stays at the same height?
It looks to me that pipe TWO is the lowest. VERY POOR DRAWING!Ever heard of angular perspective? CLEARLY pipe TWO is the lowest. UNFAIR QUESTION!
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You are correct... bad question... if assume the containers are all sitting on level ground, 2 is clearly the shortest.
the solution is wrong drawing a line somewhere does not make the solution right tank 2 has the smallest height so it will fill and overflow before the others That is simple hydraulics
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Why would the tank with the smallest height fill first? Tank 3 opens lower than tank 2, so how can tank 2 fill up before tank 3 fills up?
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Simple its height (brim) is lower, so tank 3 will overflow while the others are still filling
i didn't understand nothing about this
Presume you mean tank with the lowest brim (top)
Im having difficulty with what type of concept the problem is attempting to apply. Can any one help? Im trying to structure my thoughts in a simple and concise system in order to better understand the answer, so if possible please make a list of concepts applied.
The water will flow to the lowest point initially (ignoring the level to get to the pipes because the tank isn't full even then). After the water reaches the pipe from 3 to 5, tanks 3, 4, and 5 will even out and start to have the same water level. 3 has the lowest top among these so the water will reach there first. It will be followed by 2, 4, 5, and last would be 1.
I disagree with the last sentence of your answer. Given the two assumptions listed in the problem, tank 3 would overflow, and none of the other tanks would ever fill. 1 would fill to the level of the bottom of the pipe leaving it, the rest would fill to the height of the top of 3.
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I am assuming that the tanks had a top, stopping them from overflowing.
Height of tank 2 seems to be the lowest
Don't copy another without knowing the actual reason
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What do you mean i was the first person to post a solution on this problem. I posted it before it was a prolem of the week as well.
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Your solution was of 2 lines. And after I wrote my solution, your solution becomes larger.
Tanks 3, 4, and 5 all communicate via multiple equalizing lines. Since all are open to atmosphere, and liquids seek their own level, the lowest tank will fill and overflow first, leaving all other tanks partially empty.
Had you made it clear that all tanks were in the same vertical plane I would have answered differently. The drawing appeared to be in perspective to me.
After the lowest tank fills up, will any other tank fill up at all?
Im having difficulty with what type of concept the problem is attempting to apply. Can any one help? Im trying to structure my thoughts in a simple and concise system in order to better understand the answer, so if possible please make a list of concepts applied.
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It is very clear that the height of the pipe 3 is lowest.
So from the principle of occuring same height of water, the pipe 3 will be full at first.