Tanks

Algebra Level 1

We can fill 7 8 \frac {7}{8} of the tank A with 2 3 \frac{2}{3} of the water of the tank B.

If the tank A is empty, what is the fraction of the tank B is needed to fill completely the tank A?

16 21 \frac {16}{21} 19 24 \frac {19}{24} 21 30 \frac {21}{30} 12 26 \frac {12}{26}

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2 solutions

Anoir Trabelsi
May 10, 2014

Let x be the trank A ; y be the trank B then : 2/3 y = 7/8 x . To answer the question , we need to find x as a function of y : x = 16/21 y :)

Michael Mendrin
May 11, 2014

Scale it up: (8/7)(7/'8) = 1, so (8/7)(2/3) = (16/21)

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