Tasty Logarithm #4

Geometry Level 3

log sin ( x ) cos ( x ) + log cos ( x ) sin ( x ) = 2 \large \log_{\sin(x)} \cos (x) +\log_{\cos(x)} \sin(x) =2

If the minimum value of x x that satisfy the equation above is equals to π a \dfrac{\pi}{a} for some constant a a , find the value of a a .

Give your answer to 3 decimal places.

Note: Angles are measured in radians.

This is the part of the set .


The answer is 4.

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2 solutions

Parth Lohomi
May 13, 2015

Let log sin ( x ) cos ( x ) = m \log_{\sin(x)} \cos (x) =m

\therefore log cos ( x ) sin ( x ) = 1 m \log_{\cos(x)} \sin(x)=\frac{1}{m}

\implies m + 1 m = 2 m+\frac{1}{m}=2

m 2 + 1 = 2 m ( m 1 ) 2 = 0 , m = 1 m^2+1=2m\implies (m-1)^2=0,\therefore m=1

So, sin ( x ) = cos ( x ) x m i n = π 4 \sin(x) =\cos(x) \implies x\mid_{min} =\frac {\pi} {4}

So a = 4 a=4 .

Moderator note:

Well done using the properties of logarithm. Bonus question: What would be the solution of all x x such that the equation is fulfilled?

@Calvin Lin /@mathchallengemaster it would be n π + π 4 n\pi+\frac{\pi} {4}

Parth Lohomi - 6 years, 1 month ago

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This will be incorrect , remember that the for log a b b ( 0 , ) { 1 } and a ( 0 , ) \log_{a}{b} \quad b\in(0,\infty)-\{1\} \text{ and } a\in (0,\infty)

Both sin x \sin{x} and cos x \cos{x} should be positive , which means x should lie in the 1st Quadrant

Sabhrant Sachan - 4 years, 9 months ago

Haha We posted identical solutions at the exact same time. No point in leaving mine up any more. :)

Brian Charlesworth - 6 years, 1 month ago

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Haha, no problem!!

Parth Lohomi - 6 years, 1 month ago
Noel Lo
May 18, 2015

Interesting problem! Love it!

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