Tedious I I

Geometry Level 5

Given , a A B C \triangle ABC which is n o t o b t u s e a n g l e d not-obtuse-angled .

Now a square , a regular polygon of sides m m and another regular polygon of sides n n are constructed on sides of given triangle.

W L O G WLOG let angle A = α A=\alpha ,angle B = β B=\beta ,angle C = γ C=\gamma . Such that α β < γ \alpha \leq \beta <\gamma

Now centers of square and the 2 regular ploygons when joined form an e q u i l a t e r a l equilateral triangle .

Then find m + n + α β + γ m+n+ \alpha - \beta + \gamma .

Note : All angles are in degrees .


The answer is 102.

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1 solution

Aakash Khandelwal
Mar 29, 2016

Answer is as follows:

m = n = 6 m=n=6

α = β = 45 \alpha=\beta=45

γ = 90 \gamma=90 .

I wanna want to know the person who first solved it. After 5 days!

Please post the solution

Aakash Khandelwal - 5 years, 2 months ago

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Still one solver after 2.5 months, still no solution

Aakash Khandelwal - 4 years, 12 months ago

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