Evaluate:
1 × 2 1 + 2 × 3 1 + 3 × 4 1 + ⋯ ⋯ ⋯ + 9 9 × 1 0 0 1
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the last term is1/(99*100), so 99/100=.99
Since all units are getting cancelled by + and - values except 1 and 1/99X100.therefore sum of remaining items will be 1 plus 1/99 -1/100 and that is 1.000101 Ans.
K.K.GARG,India
1/1 2+1/2 3+1/3*4.......1/(n)(n+1) = n/(n+1) (where n is the no. of terms) since there are 99 terms the answer is 99/(99+1) which is = 99/100=0.99
According to the pattern, the previous problem showed the answer 3/4 when all the sums were added. 3/4 were last fraction's 3 x 4. Therefore, the last fraction here is 1/(99x100) and the answer is 99/100; which is 0.99 in decimal or 1.0 if you estimate it.
we have: 1/[n.(n+1)]= 1/n- 1/(n+1) => 1/(1.2) + 1/(2.3) + ....+ 1/(99.100) = 1-1/2+1/2-1/3+...+1/99-1/100=1-1/100= 99/100
100/101 = 0.990099009901
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1/1*2 will be split as 1-1/2 If we do it simultaneously we get 1-1/2 plus 1/2-1/3 We will get alternative plus and minus no of same value They will get cancelled and the remaining no will be 1-1/100 we get 99/100 so the answer is 0.99