Ten divisors

Number Theory Level pending

What is the smallest positive integer with 10 divisors?


The answer is 48.

Munem Shahriar by Munem Shahriar , 18, Bangladesh

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1 solution

Pepper Mint
Oct 18, 2017

The number of the divisors on a b × c d a^b \times c^d is ( b + 1 ) ( d + 1 ) (b+1)(d+1) . So, the minimum integer should be 2 4 × 3 1 = 48 2^4 \times 3^1=48 .

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a b × c d a^b \times c^d is ( c + 1 ) ( d + 1 ) (c+1)(d+1) . So, the minimum integer should be 2 4 × 3 1 = 48 2^4 \times 3^1=48 .?

Nazmus sakib - 3 years, 7 months ago

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b, not c. Thanks

Pepper Mint - 3 years, 7 months ago

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