Ten Lords a Leaping
There are 10 men in a line who each holds a number. That number is their number in the line starting from the front. (i.e. If Aaron is the first in line, he carries the number 1. If Bam is the second in line, he carries the number 2, and so on and so forth.)
What is the sum of all their numbers?
The answer is 55.
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Since there are 10 men in a line, and the number they are carrying is their number from the front of the line. So, it is sure that the numbers are: 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10. And you just add them all:
1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 55
Another way is using this formula:
The sum of the first n natural numbers:
here's a link
Wherein:
n = 10
=> 10(10 + 1) / 2
=> 10(11)/2
=> 110/2
=> 55
So, 55 is the answer.