Ten ten

Factoring a $5$ out of the top we see that we have $5*\frac{1+2+3+4+5+6+7+8+9+10}{1+2+3+4+5+6+7+8+9+10}$ . This simplifies to $5$

$\frac{5 + 10 + 15 + 20 + 25 + 30 + 35 + 40 + 45 + 50}{1+2+3+4+5+6+7+8+9+10} = \frac{5 (1+2+3+4+5+6+7+8+9+10)}{1+2+3+4+5+6+7+8+9+10} = 5$

$\frac{5+10+15+20+25+30+35+40+45+50}{1+2+3+4+5+6+7+8+9+10}$ $=\frac{5 \times(1+2+3+4+5+6+7+8+9+10)}{1+2+3+4+5+6+7+8+9+10}$ $=\boxed{5}$ Therefore, the answer is $\boxed{5}$ .

The sum of n terms in arithmetic progression is s_n=1/2 n(a+l) where n=number of terms a=initial value and l=final value =(1/2 10(5+50))/(1/2 10(1+10)) =(10(55))/(10(11)) =5

(5+10+15+20+25+30+35+40+45+50)/(1+2+3+4+5+6+7+8+9+10) = 5(1+2+3+4+5+6+7+8+9+10)/(1+2+3+4+5+6+7+8+9+10) . = 5

The numerator can be written as $5(1+2+3+4+5+6+7+8+9+10)$ Simplify with the denominator and you get $\boxed{5}$

One arithmetic sequence divided by another. Use arithmetic sum formula (n*(a 1+a n)/2 or simply factor 5 out of the numerator.

(1/2 10(5+50))/(1/2 10(1+10)) =(10(55))/(10(11)) =5

firstly,(5+50)+(10+45)+............+(25+30)=(55x5) , secondly,(1+10)+(2+9)+........+(5+6)=11x5 then,(55x5)/(11x5)=5....answer..

(5+10+15+20+25+30+35+40+45+50)/(1+2+3+4+5+6+7+8+9+10)=5.(1+2+3+4+5+6+7+8+9+10)/(1+2+3+4+5+6+7+8+9+10)=5

275/45=5

You could add up all the numbers that are on the numerator and get 295.Then divide the sum of the denominator which is 55. However, you could figure out the two middle numbers' on the numerator's sum which is 55 (25+30).Then divide the 55 by the middle numbers' total which is 11 (5+6). The answer you will then get is 5

TAKE 5 common...easy!

$\frac{5+10+15+...+50}{1+2+3+...+10} = \frac{5(1+2+3+...+10)}{(1+2+3+...+10)} = 5$

(5+10+15+20+25+30+35+40+45+50)/5 = 5(1+2+3+4+5+6+7+8+9+10)/(1+2+3+4+5+6+7+8+9+10) = [5(55)]/55 = 5

5(1+2+3+4+5+6+7+8+9+10),then ans is 5

10/2 (5+50)/[10 11/2)=5*55/55=5 and one thing mre pls bring back old brillliant

5(1+2+3+4+5+6+7+8+9+10)/(1+2+3+4+5+6+7+8+9+10) = 5

take 5 common from all the terms from the numerator.. u will get the denominator so both will cancel and u will get the common 5 as the answer.

take 5 common from the numerator equation becomes

5(1+2+3+4+5+6+7+8+9+10)/(1+2+3+4+5+6+7+8+9+10)

hence answer is 5

5 + 10 + 15 + 20 + 25 + 30 + 35 + 40 + 45 + 50 = 5 x (1+ 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10). So result is 5