Find the ten's digit of the expression:
(1! + 2! + 3! + ... + 100!)
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
The ten's digit is only dependent on (1! +2! + 3! + ... + 9! ) as 10! has two zeros and the number of trailing zeros keeps increasing thereafter. So, 1 + 2 + 6 + 24 + 20 + 20 + 40 + 20 + 80 (only last two digits) = 1(ten's digit)