A rope of mass 5kg is moving vertically in vertical position with an upward force of 100N acting at the upper end and a downward force of 70N acting at the lower end. The tension midpoint of the rope is
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The acceleration of the rope is (100-70)/5= 6m/s.s
For the lower half part of the rope(of mass 2.5 kg), two forces act, Tension(T) and 70N.
Therefore, T-70 = 2.5 x 6, [ F=m.a] , giving T=85 N.