Tent

Geometry Level 2

E D A B D B A C A B = A C C = 90 ° D = 102 ° ED\parallel AB\\ DB\parallel AC\\ AB=AC\\ \angle C=90°\\ \angle D=102°

Find B C F \angle BCF


The answer is 39.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

X X
May 28, 2018

A C B = 102 2 = 51 , B C F = 90 51 = 39 \angle{ACB}=\frac{102}2=51,\angle{BCF}=90-51=39

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...