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Calculus Level 4

Find the value of n = 1 3 n . 5 n ( 5 n 3 n ) ( 5 n + 1 3 n + 1 ) \Large \displaystyle \sum_{n=1}^{\infty} \dfrac{3^n.5^n}{(5^n-3^n)(5^{n+1}-3^{n+1})}


You can try my other Sequences And Series problems by clicking here : Part II and here : Part I.


The answer is 0.75.

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1 solution

U Z
Nov 16, 2014

T n = 3 n . 5 n 5. 5 2 n + 3. 3 2 n 8. 3 n 5 n T_{n} = \dfrac{3^{n}.5^{n}}{5.5^{2n} + 3.3^{2n} - 8.3^{n}5^{n}}

1 5. 5 n 3 n + 3. 3 n 5 n 8 \dfrac{1}{5.\frac{5^{n}}{3^{n}} + 3.\frac{3^{n}} {5^{n}} - 8}

5 n 3 n = x \dfrac{5^{n}}{3^{n}} = x

= 1 5 x 5 + 3 x 3 =\dfrac{1}{5x - 5 + \dfrac{3}{x} - 3}

1 ( x 1 ) ( 5 3 x ) \dfrac{1}{(x-1)(5 - \dfrac{3}{x})}

1 x . ( 1 1 x ) ( 2 + 3 ( 1 1 x ) \dfrac{1}{x.(1 - \dfrac{1}{x})(2 + 3(1 - \dfrac{1}{x})}

3 2 x ( 2 3 ( 1 1 x ) ( 2 + 3 ( 1 1 x ) ) \dfrac{3}{2x}(\dfrac{2}{3(1 - \dfrac{1}{x})(2 + 3(1 - \dfrac{1}{x})})

3 2 x ( 1 3 ( 1 1 x ) 1 2 + 3 ( 1 1 x ) ) \dfrac{3}{2x}(\dfrac{1}{3(1 - \dfrac{1}{x})} - \dfrac{1}{2 + 3(1 - \dfrac{1}{x})})

= 1 2 ( 3 n 5 n 3 n 3 n + 1 5 n + 1 3 n + 1 ) = \dfrac{1}{2}(\dfrac{3^{n}}{5^{n} - 3^{n}} - \dfrac{3^{n + 1}}{5^{n + 1} - 3^{n + 1}})

= 3 4 = \dfrac{3}{4}

Good........work

Ayush Verma - 6 years, 6 months ago

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Once again Thank you sir

This image is copied from John Muradeli comment

U Z - 6 years, 6 months ago

Doing great. Very good. Keep it up. @megh choksi

Sandeep Bhardwaj - 6 years, 6 months ago

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thank you , same to you sir

This image is copied from John Muradeli comment

U Z - 6 years, 6 months ago

Completed your set. Great questions sir. Please add some more..

Kïñshük Sïñgh - 6 years, 6 months ago

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One question wrong and one question left , Completely agree with you sir,

Please add more @Sandeep Bhardwaj

U Z - 6 years, 5 months ago

The Same! Keep posting these type of problems, SiR!!

Rudresh Tomar - 6 years, 5 months ago

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Wow that was a great question. It took me a long time to solve it.

Aditya Tiwari - 6 years, 5 months ago

Nicely Done. Great Question !

Keshav Tiwari - 6 years, 4 months ago

Yup did the same

Daniel Mathew - 3 years, 5 months ago

This problem is virtually identical to Problem A2 of the 1984 Putnam Exam.

tom engelsman - 8 months, 3 weeks ago

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