Termz

Use the formula for the $n^{th}$ term of an arithmetic progression.

$a_n=a_1+(n-1)d$

$152=2+(n-1)(3)$ $\implies$ $152=3n-1$ $\implies$ $\color{#D61F06}\boxed{n=51}$

the sequence is going as=2, 5, 8, 11................

the difference is 3.

so, looking at the options this is clear that 51 will be the answer.

if it cross 100th sequence this will definitely pass 300+....

3×1 - 1 =2 the entire sequence is of same form so 152 comesat 3×51 -1 I.e, at 51st position

It is observed that the question is in the form of: (Table of 3)-1 So, just divide (152+1)/3 and the answer is: 153/3=51