A motorcyclist turns a sharp left corner by applying equal but opposite forces of 40N to the ends of the handlebars. The length of the handlebars 0.67m. Calculate the torque applied to the end of the handlebars. Give your solution to 1 decimal place.
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
T=F*D Substitute the values 40N for force and 0.67m for perpendicular distance between the forces. Thus 40N multiplied by 0.67m= 26.8