Tessellate S.T.E.M.S - Physics - College - Set 3 - Problem 2

In the cycle AEBFA given below, both AEB and BFA are reversible processes. Also, during the process AEB, the system (only)absorbs heat $Q_2$ and during the process BFA , the system (only) releases heat $Q_1$ , i.e. $\delta Q_2 > 0$ and $\delta Q_1<0$ . Then which of the following statements are correct ?

$(i)\int_{AEB} \frac{\delta Q}{T} = \int_{AFB} \frac{\delta Q}{T}$

$(ii)$ Entropy of the system increases.

$(iii)$ The total work done equals to the net heat absorbed $Q_2 - Q_1$ .

$(iv)$ Efficiency of the cycle is independent of the type of reversible process.

$(v)$ Efficiency of the cycle is unchanged irrespective of the reversibility condition

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This problem is a part of Tessellate S.T.E.M.S.